STOCHASTIC EPIDEMIC MODELS WITH POISSON INFECTIVES AND CARRIERS
S.Revathi, Assistant Professor1, C.Nithya, Assistant Professor2
Department Of Statistics,
Marudhar Kesari Jain College For Women, Vaniyambadi1
Department Of Mathematics
Marudhar Kesari Jain College For Women, Vaniyambadi2
Mail id: revathiramesh06@gmail.com1
Mail Id: nithimadhavan287@gmail.com2
Abstract
In this Paper, we have derived stochastic epidemic models Poisson infection, carrier and removal rates. Stochastic modelling of epidemic is importent when the number of infectious individuals is small or when the variability in transmission, recovery, births, deaths or the environment impacts the epidemic outcome.
Keywords: Epidemics, Susceptible, infection rate, carrier, removal rate.
Introduction
An Epidemic is the rapid spread of infections disease to a large number of people in a given population within a short period of time, usually two weeks or less. An Epidemic may be restricted to one location, however if it spreads to other countries or continents and affects a substantial number of people, it may be termed a pandemic. The occurrence of more cases of a disease than would be expected in a community or region during a given time period is called an epidemic. We have derived stochastic epidemic models carrier rates with Poisson infection.
1. Definition
An Epidemic is an usually large short term outbreak of a disease, such as cholera and Plague etc….
The spread of disease depends on
(i) The mode of transmission
(ii) Susceptibility
(iii) Infections period
(iv) Resistance and many other facts.
1.1 Definition
The population in an epidemiological model can be classified into three types.
(i) Susceptible – S(t)
(ii) Infected – I(t)
(iii) Removal – R(t)
Where S(t) = number of individuals in the population who can be infected
I(t) = number of infected individuals in the population
R(t) = number of individuals removed from population by recovery, death, immunization.
1.2Definition
Consider the discrete random variable which taking the non negative values
(i.e) ππ=π(π=π) where k = 0,1,2,3……
The probability generating function X is defined as
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πΊπ(π)=Ξ£ππππ=πΈ(ππ)∞π=0
Note
Consider π΄1π΄2….π΄π be a partition of Ξ©, for any event B
Pr(π΅)= Ξ£Pr(π΄π)Pr (π΅/π΄π)ππ=1
2. Stochastic Epidemic Model with Infectives and Carries
Let m, n, p denote the number of susceptible, infectives and carriers. A susceptible can become infective by contact with either an infected or a carrier. The result is represented in the following model.
Let ππ,π,π(t) be the probability that there are m susceptible, n infectives and p carriers in the population at time t. If N is the total size of the population, then the number of persons in the removed category is N-m-n-p.
Let the probability of a susceptible being infected in the time interval (t, t + Ξπ‘) be π½mnΞπ‘ + O(Ξπ‘), and let the probability of a susceptible being infected due to contact with a carrier in the time interval (t,t + Ξπ‘) be πΎmpΞπ‘ + O(Ξπ‘), and also let the corresponding probability of one carrier being removed in the same time interval be πΏπΞπ‘ + O(Ξπ‘).
In this case, we assume that π½mn is the Poisson rate of susceptible becomes infected with parameter ππΌ , πΎmp is the Poisson rate of susceptible becomes infected due to contact with a carrier with parameter ππΆ , and πΏP is the Poisson rate of carrier becomes removed with parameter ππ .
i.e, π½mn = = π−ππΌ ( ππΌ)π π!, m≥0 ( 1)
πΎmp = π−ππΆ ( ππΆ)π π! , m≥0 (2)
πΏπ= π−ππ ( ππ )π π! , p≥0 ( 3)
Here, ππΌ be the rate of infection from susceptible to infected, ππΆ be the rate of carrier and ππ be the rate of removal carrier to removed.
The probability that there is no change in the time interval (t, t + Ξπ‘) is then given by
1- π½mn Ξπ‘ - πΏπ Ξπ‘ + O (Ξπ‘) ( 4)
Now there can be m susceptible , n infectives and p carriers at the time t + Ξπ‘ if there are
a) m+1 susceptibles , n-1 infectives and p carriers at the time t and if one person has become infected in time Ξπ‘, (or)
b) m+1 susceptibles , n-1 infectives and p carriers at the time t and if one person has become infective due to contact with a carrier in time Ξπ‘, (or)
c) m susceptibles , n infectives and p +1 carriers at the time t and if one carrier has been removed in time Ξπ‘, (or)
d) m susceptibles , n infectives and p carriers at the time t and if there is no change in time Ξπ‘.
We assume that the probability of more than one change in time Ξπ‘ is π(Ξπ‘).
Then, using the theorems of total and completed probability , we get
ππ,π,π(t + Ξπ‘) = ππ+1,π−1,π (t) π½ (m+1) (n-1) Ξπ‘ + ππ+1,π−1,π (t) πΎ (m+1) p Ξπ‘
+ ππ,π,π+1(t) πΏ (p+1) Ξπ‘ + ππ,π,π (t) (1- π½mn Ξπ‘ - πΏπ Ξπ‘) + O (Ξπ‘)
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So that,
ππ,π,π(t + Ξπ‘) = ππ+1,π−1,π (t) π½ (m+1) (n-1) Ξπ‘ + ππ−1,π−1,π (t) πΎ (m+1) p Ξπ‘
+ ππ,π,π+1(t)πΏ (p+1) Ξπ‘ + ππ,π,π (t) - ππ,π,π (t)π½mn Ξπ‘
- ππ,π,π (t) πΏπ Ξπ‘) + O (Ξπ‘)
ππ,π,π(t + Ξπ‘) - ππ,π,π (t) = ππ+1,π−1,π (t) π½ (m+1) (n-1) Ξπ‘ + ππ+1,π−1,π (t) πΎ (m+1) p Ξπ‘
+ ππ,π,π+1(t)πΏ (p+1) Ξπ‘ - ππ,π,π (t)π½mn Ξπ‘
- ππ,π,π (t) πΏπ Ξπ‘ + O (Ξπ‘) (5)
Dividing on the both sides by Ξπ‘ , and proceeding to the limit as Ξπ‘ →0 in ( 5 ) we get
limΞπ‘→0 ππ,π,π(t + Ξπ‘) − ππ,π,π (t)Ξπ‘ = ππ+1,π−1,π (t) π½ (m+1) (n-1) + ππ+1,π−1,π (t) πΎ(m+1) p
+ ππ,π,π+1(t)πΏ (p+1) - ππ,π,π (t) π½mn
- ππ,π,π (t) πΏπ + O
Therefore,
πππ‘ (ππ,π,π(t)) = π½ (m+1) (n-1) ππ+1,π−1,π (t) - π½mn ππ,π,π (t) + πΎ(m+1) p ππ+1,π−1,π (t)
+ πΏ (p+1) ππ,π,π+1(t) – πΏπ ππ,π,π (t)
Initially, let there be a susceptible, b infective and c carriers.Then we define the probability generating function
πππ‘(ΣΣΣππ,π,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§ππ+π−ππ=0ππ=0) =
ΣΣΣπππ‘π+π+π−π−ππ=0π+π−ππ=0ππ=0 (ππ,π,π (t)) π₯ππ¦ππ§π ( 6 )
Multiplying ( 6) by π₯ππ¦ππ§π and summing over p from 0 to π+π+π−π−π;π ππππ 0 π‘π π+π−π πππ π ππππ 0 π‘π π, we get
πππ‘(ΣΣΣππ,π,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§ππ+π−ππ=0ππ=0) =
ΣΣΣπππ‘π+π+π−π−ππ=0π+π−ππ=0ππ=0 (ππ,π,π (t)) π₯ππ¦ππ§π
So that,
ππππ‘ = ΣΣΣ{ π½π+π+π−π−ππ=0π+π−ππ=0ππ=0 (m+1) (n-1) ππ+1,π−1,π(π‘)-π½mnππ,π,π(t)
+πΎ(π+1)π ππ+1,π−1,π(π‘)+ πΏ (π+1)ππ,π,π+1(π‘) –
πΏπ ππ,π,π(π‘) } π₯ππ¦ππ§π
= π½ { ΣΣΣ(π+1)(π−1)ππ+1,π−1,ππ+π+π−π−π π=0(π‘)π₯ππ¦ππ§ππ+π−ππ=0ππ=0 –
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ΣΣΣππππ,π,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§ππ+π−ππ=0ππ=0 }
+πΎ {ΣΣΣ(π+1)πππ+1,π−1,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§ππ+π−ππ=0ππ=0
+πΏ {ΣΣΣ(π+1)ππ,π,π+1π+π+π−π−ππ=0(π‘)π₯ππ¦ππ§π−π+π−ππ=0ππ=0
ΣΣΣπππ,π,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§ππ+π−ππ=0ππ=0 }
Now , the definition of probability generating function , we have
π₯ ππππ₯ = ΣΣΣπ πππππ,π,π (t) π₯ππ¦ππ§π ;
π¦ ππππ¦ = ΣΣΣπ πππππ,π,π (t) π₯ππ¦ππ§π ;
π§ ππππ§ = ΣΣΣπ πππππ,π,π (t) π₯ππ¦ππ§π ;
π₯π¦ π2πππ₯ππ¦ = ΣΣΣππ πππππ,π,π (t) π₯ππ¦ππ§π ; and π₯π§ π2πππ₯ππ§ = ΣΣΣππ πππππ,π,π (t) π₯ππ¦ππ§π .
∴ππππ‘ = π½{ π¦2ΣΣΣ(π+1)(π−1)π+π+π−π−ππ=0π+π−ππ=0ππ=0 ππ+1,π−1,π (t)
π₯ππ¦π−2π§π – π₯π¦ ΣΣΣπππ+π+π−π−ππ=0π+π−ππ=0ππ=0 ππ,π,π (t) π₯π−1π¦π−1π§π }
+ πΎ {π§Ξ£Ξ£Ξ£(π+1)πππ+1,π−1,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§π−1π+π−ππ=0ππ=0 }
+ πΏ {ΣΣΣ(π+1)ππ,π,π+1π+π+π−π−ππ=0(π‘)π₯ππ¦ππ§π−π+π−ππ=0ππ=0
π§ ΣΣΣπππ,π,ππ+π+π−π−ππ=0(π‘)π₯ππ¦ππ§π−1π+π−ππ=0ππ=0 } (7)
By using the above relation ,we get
ππππ‘ = π½ ( π¦2 π2πππ₯ππ¦− π₯π¦ π2πππ₯ππ¦ )+ πΎ (π§ π2πππ₯ππ§ )+ πΏ (ππππ§−π§ ππππ§ )
that is, ππππ‘ = π½ (π¦2−π₯π¦ ) π2πππ₯ππ¦+ πΎπ§ π2πππ₯ππ§+ πΏ (1−π§)ππππ§ ( 8)
3. Classification of the solutions
We find the classification of the solution of the partial differential equation in equation (8).
Now, find a linear partial differential equation of the second order in four independent variables π₯,π¦,π§ and t.
Equation (8) can be written as
0.ππ₯π₯ + π½2 (π¦2− π₯π¦) ππ₯π¦ +πΎ2 π§ππ₯π§+0. ππ₯π‘ + π½2 (π¦2− π₯π¦) ππ¦π₯
+ 0.ππ¦π¦ + 0.ππ¦π§ + 0.ππ¦π‘+ πΎ2 π§ππ§π₯+ 0.ππ§π¦ +0.ππ§π§+0.ππ§π‘+0.ππ‘π₯
+0.ππ‘π¦+ 0.ππ‘π§ +0.ππ‘π‘ +0.ππ₯+0.ππ¦+Ξ΄ (1−z)Οz−1.Οt+0.Ο=0 (9)
Let us define the matrix A, is given by
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A= [ πππππ.ππ π’π₯π₯πππππ.ππ π’π¦π₯πππππ.ππ π’π§π₯πππππ.ππ π’π‘π₯ πππππ.ππ π’π₯π¦πππππ.ππ π’π¦π¦πππππ.ππ π’π§π¦πππππ.ππ π’π‘π¦ πππππ.ππ π’π₯π§πππππ.ππ π’π¦π§πππππ.ππ π’π§π§πππππ.ππ π’π‘π§ πππππ.ππ π’π₯π‘πππππ.ππ π’π¦π‘πππππ.ππ π’π§π‘πππππ.ππ π’π‘π‘ ] (10)
Therefore, A = [ 0π½2 (π¦2− π₯π¦)πΎ2 π§0 π½2 (π¦2− π₯π¦)000 πΎ2 π§000 0000]
Since, πππ= πππ , π¨= [πππ]ππΏπ is a symmetric matrix of order 4 x 4.
So that,
|π΄| = ||0π½2 (π¦2− π₯π¦)πΎ2 π§0 π½2 (π¦2− π₯π¦)000 πΎ2 π§000 0000|| = 0
Also, the Eigen values of A is given by the form |π΄−ππΌ|=0
||−ππ½2 (π¦2− π₯π¦)πΎ2 π§0 π½2 (π¦2− π₯π¦)−π00 πΎ2 π§0−π0 000−π|| = 0
That is,
π4− π2 π½22 (π¦2− π₯π¦)2− π2 πΎ24 (π§)2 =0
π2 (π2− π½22 (π¦2− π₯π¦)2− πΎ24 (π§)2 =0)
Ξ» = 0, 0; π2= π½22 (π¦2− π₯π¦)2+ πΎ24 (π§)2
Therefore,
Ξ» = 0, 0; Ξ» = 12 √π½2(π¦2− π₯π¦)2+ πΎ2 π§2
in above equations, the determinant value of A is zero and one of the Eigen values of A is also zero. the solution of the given partial differential equation (8) is of parabolic type.
Conclusion
Hence we have classified the stochastic epidemic models by considering infectives, carriers and removal rates. There are three types of removal recovery, immunization and death this can be elaborately studied by considering each of the removals separately.
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[2] Burghes DN, Borrie M.S. Modeling with differential equations, Ellis Horwood Ltd, 1981.
[3] Diekmann O, Heesterbeek JA. Mathematical epidemics of infectious diseases: Model
building, analysis and interpretation, John Wiley, New York, 2000.
[4] Hethcote HW. Three basic epidemiological models. In S.A. Levin, editor, Lect. Notes
in Biomathematics, Springer-Verlag Heidelberg. 1994; 100:119-144.
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